How do you write this in a algebraic equation: 6 more than 7 times a number is 41

[tex]x-number\\\\7\ times\ a\ number:7x\\\\6\ more\ than\ 7\ times\ a\ number:7x+6\\\\6\ more\ than\ 7\ times\ a\ number\ is\ 41:7x+6=41\\\\solution:\\\\7x+6=41\ \ \ \ |subtract\ 6\ on\ both\ sides\\\\7x=35\ \ \ \ \ |divide\ both\ sides\ by\ 7\\\\x=5[/tex]