## Answer :

**Yes, I can.**

__Answer:__Although you haven't asked for the solution, here it is anyway:

2^x = e^(x+2)

x ln(2) = x+2

x ln(2) - x = 2

x [ ln(2) - 1 ] = 2

x = 2 / [ ln(2) - 1 ]

x = 2 / -0.3069... =

**... (rounded)**

__- 6.518__Although you haven't asked for the solution, here it is anyway:

2^x = e^(x+2)

x ln(2) = x+2

x ln(2) - x = 2

x [ ln(2) - 1 ] = 2

x = 2 / [ ln(2) - 1 ]

x = 2 / -0.3069... =