## Answer :

[tex] \frac{3}{8} + \frac{3}{8} + \frac{3}{8} = \frac{9}{8} = 1\frac{1}{8} [/tex] which is more than 1, but....

[tex] \frac{3}{8} + \frac{3}{8} = \frac{6}{8} [/tex]

The answer is 2

[tex]1= \frac{8}{8} [/tex]

[tex] \frac{8}{8} - \frac{6}{8} = \frac{2}{8} [/tex]

**The answer is 2**with a remainder of 2/8 or 1/4 or 0.25

The **number **of 3/8's that are in 1 is [tex]2\frac{2}{3}[/tex]

From the question,

We are to determine the **number **of **3/8's** that are in** 1**.

To do this, we will **divide **1 by 3/8

The** division operation** is carried out as shown below

[tex]1 \div \frac{3}{8}[/tex]

This becomes

[tex]1 \times \frac{8}{3}[/tex]

= [tex]\frac{8}{3}[/tex]

= [tex]2\frac{2}{3}[/tex]

Hence, the **number **of 3/8's that are in 1 is [tex]2\frac{2}{3}[/tex]

**Learn more here**: https://brainly.com/question/9145170