## Answer :

Ka = [H+][CO3 2-]/[HCO3-]

[ ] = concentration

then solve for [H+] if you know the Ka of HCO3-, and then take the -log[H+] to find the pH.

The Ka of HCO3- = 5.6x10^-11

Ka = [H+][CO3 2-]/[HCO3-]

[ ] = concentration

then solve for [H+] if you know the Ka of HCO3-, and then take the -log[H+] to find the pH.

The Ka of HCO3- = 5.6x10^-11